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Oracle·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Jun 2026

Summary

Oracle SWE interview, got a classic LRU cache design question. Pretty standard for this kind of role but the O(1) constraint is where things get interesting if you haven't thought it through before.

Questions Asked (1)

Q1

Design and implement an LRU cache with get and put operations, both running in O(1) average time complexity.

Algorithms & Data StructuresSystem Design
Author's notes

The part that trips people up isn't the cache logic itself, it's the O(1) eviction.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the requirements: O(1) get and put, capacity limit, and eviction policy (least recently used). Then propose a combination of a hash map for O(1) access and a doubly linked list for O(1) updates to recency order. Walk through the design, implement the core operations, and analyze time and space complexity.

Pro tip: Mention edge cases like updating an existing key, evicting when at capacity, and handling capacity 0 or 1. Also, discuss thread-safety if the cache will be used in a concurrent environment, as Oracle often values robustness in production systems.

1. Clarify Requirements

Confirm the cache capacity, eviction policy (LRU), and whether operations need to be thread-safe. Ask about expected usage patterns to tailor the design.

2. Choose Data Structures

Select a hash map for O(1) key lookup and a doubly linked list to maintain recency order. Explain how the map stores nodes of the list for direct access.

3. Design Operations

Define get: if key exists, move node to front and return value; else return -1. Define put: if key exists, update value and move to front; else add new node to front and evict least recently used (tail) if over capacity.

4. Implement and Test

Write clean code for the LRU cache class, handling edge cases like capacity 0 or 1. Test with scenarios including repeated gets, puts, and evictions.

5. Analyze Complexity

State that both get and put run in O(1) average time due to hash map and linked list operations. Space complexity is O(capacity) for storing the map and list.

Key Points to Mention

  • Hash map provides O(1) average time for key lookup.
  • Doubly linked list allows O(1) removal and insertion for recency updates.
  • Eviction policy: remove the least recently used item, which is the tail of the list.
  • Handling updates: when putting an existing key, update value and move node to front.
  • Edge cases: capacity 0, capacity 1, and eviction when full.
  • Thread-safety considerations (e.g., using locks or concurrent data structures) if needed.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.