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Squarepoint·Data Scientist·Technical Phone Screen·Intermediate

Intermediate
Jul 2026

Summary

Squarepoint Data Scientist interview had a pretty math-heavy quantitative finance angle. The main question was about Sharpe ratios and what happens when you filter out zero-return observations. Not the usual ML or SQL stuff I'd prepped for.

Questions Asked (1)

Q1

You have a return series with 2n observations, exactly half of which are zero. Compare the Sharpe ratio computed on all 2n observations versus the Sharpe ratio computed only on the n non-zero observations. Is the filtered Sharpe higher or lower, and does it depend on the sign of the mean return? Also, does the conclusion change if the n removed observations aren't necessarily the zero ones?

Product Analytics & MetricsTechnical Trade-offs
Author's notes

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AI HintsAI Generated

Suggested Approach

Start by writing the Sharpe ratio formula and expressing the filtered Sharpe in terms of the full-sample mean and standard deviation, noting that removing zeros changes both. Then analyze the ratio of the two Sharpe ratios to determine when the filtered Sharpe is higher or lower, considering the sign of the mean. Finally, generalize by considering arbitrary removal of n observations and discuss the impact on the Sharpe ratio.

Pro tip: Emphasize that the Sharpe ratio is not invariant to removing zero returns; it depends on the signal-to-noise ratio. A common mistake is to assume that removing zeros always improves the Sharpe ratio, but it can actually decrease it if the mean return is negative.

1. Define the Sharpe ratios

Let the full sample have 2n observations with n zeros. Compute the full-sample Sharpe ratio S_full = μ_full / σ_full, where μ_full is the mean and σ_full is the standard deviation. Compute the filtered Sharpe ratio S_filt = μ_filt / σ_filt using only the n non-zero observations.

2. Express filtered statistics in terms of full-sample statistics

Relate μ_filt and σ_filt to μ_full and σ_full. Since half the observations are zero, μ_full = μ_filt / 2. Also, the sum of squares of the full sample equals the sum of squares of the non-zero observations, so σ_full^2 = (1/(2n)) Σ x_i^2 - (μ_filt/2)^2, while σ_filt^2 = (1/n) Σ x_i^2 - μ_filt^2. Derive the relationship between σ_full and σ_filt.

3. Compare the Sharpe ratios

Form the ratio S_filt / S_full = (μ_filt / σ_filt) / (μ_full / σ_full) = 2 * (σ_full / σ_filt). Determine whether this ratio is greater than 1, which depends on the sign of μ_filt and the relative variability. Show that S_filt > S_full if and only if μ_filt > 0 (assuming non-zero variance).

4. Generalize to arbitrary removal of n observations

Consider removing any n observations, not necessarily zeros. The filtered Sharpe ratio can be higher or lower depending on which observations are removed. Discuss that removing low-volatility or negative-mean observations can increase the Sharpe ratio, while removing high-mean observations can decrease it. The conclusion depends on the properties of the removed subset.

Key Points to Mention

  • Sharpe ratio is defined as mean excess return divided by standard deviation of returns.
  • Removing zeros reduces the sample size and changes both the mean and standard deviation.
  • The filtered Sharpe ratio is higher than the full-sample Sharpe ratio if and only if the mean return of the non-zero observations is positive.
  • If the mean return is negative, removing zeros makes the Sharpe ratio more negative (lower).
  • The conclusion depends on the sign of the mean return, not just the presence of zeros.
  • When removing arbitrary observations, the effect on the Sharpe ratio depends on the mean and variance of the removed subset relative to the remaining data.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.