← Snowflake Interview Insights
My first instinct was to sort by revenue and just pick the highest one, which is wrong.
For each query type, compute the maximum number of times it can run within K minutes (floor(K / runtime_i)) and multiply by its per-run revenue to get total revenue. Then select the query type with the highest total revenue. This is an O(n) scan, and you should discuss edge cases like zero runtime or zero revenue.
Pro tip: Mention that this is a classic fractional knapsack variant where the constraint forces choosing exactly one item type, so the greedy choice by total revenue is optimal. Also, clarify that if runtimes don't divide K evenly, leftover time is wasted, which can affect the choice.
Restate the problem: you have K minutes, n query types each with fixed runtime and revenue per run, and you must pick exactly one type to run repeatedly. The goal is to maximize total revenue.
For each query type i, calculate the number of runs as floor(K / runtime_i) and total revenue as runs * revenue_i. Note that any leftover time cannot be used.
Iterate through all query types, compute total revenue for each, and keep track of the maximum. Return the query type that yields the maximum revenue.
The algorithm runs in O(n) time and O(1) extra space. Discuss edge cases: runtime > K (zero runs), zero revenue, zero runtime (infinite runs, but likely invalid), and ties.
If the problem allows, consider precomputing or using a priority queue for dynamic updates, but for a single query, the linear scan is optimal.
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