I knew the shape of the solution pretty fast: group by user, sort by time, build a trie, DFS print with indentation.
First, sort the log by user_id and timestamp to reconstruct each user's action sequence. Then, for each user, build the path string (e.g., 'login > view > purchase') and count how many distinct users have each path. Finally, insert these paths into a trie and output the trie as an indented tree with user counts at each node.
Pro tip: Clarify whether the path should be based on the full sequence of actions or only unique actions in order, and whether timestamps with equal values need a tie-breaker. Also, mention that you'd handle out-of-order logs by sorting, which is O(n log n), and that a trie naturally aggregates counts and supports the tree output.
Ask about the definition of a 'path' (full sequence vs. unique actions), how to handle ties in timestamps, and whether the output should include counts at each node or only leaves. Also confirm if users with no actions should be ignored.
Sort the log entries by user_id and then by timestamp to reconstruct each user's action sequence. If timestamps are equal, use a stable sort or an additional tie-breaker like action name.
For each user, concatenate their actions in order to form a path string (e.g., 'A>B>C'). Use a hash map to count how many distinct users have each path.
Insert each unique path into a trie, where each node represents an action and stores the count of users whose path passes through that node. This aggregates counts for shared prefixes.
Perform a depth-first traversal of the trie, printing each node with indentation proportional to its depth and appending the user count. Ensure the output is sorted alphabetically or by count for consistency.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.