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Start by clarifying that in a DAG with multiple parents, the Lowest Common Ancestor (LCA) of two nodes is the deepest node that is an ancestor of both, where depth is measured by longest path from a source. Then describe an algorithm that computes all ancestors of each node (e.g., via topological order and bitsets) and finds the common ancestor with maximum depth.
Pro tip: Mention that bitsets are efficient for dense graphs, but for sparse graphs, a hash set intersection or iterative marking may be more memory-friendly; also note that the LCA may not be unique if multiple nodes share the same maximum depth, so clarify tie-breaking or return all.
Explain that LCA is the common ancestor with the greatest depth (longest path from any source), and note that there can be multiple LCAs if they share the same depth.
Process nodes in topological order, maintaining a set (or bitset) of ancestors for each node by unioning the ancestor sets of all its parents plus the parents themselves.
Intersect the ancestor sets of the two target nodes, then among the common ancestors, select the one(s) with the maximum depth (precomputed via longest path from sources).
Discuss time and space complexity: O(V+E) for topological sort, O(V^2/word_size) for bitset unions, and O(V) for intersection; mention alternatives like iterative marking for sparse graphs.
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