The example they gave makes it click pretty fast: 12 and 21 are the same group, 34 and 43 are the same group.
Clarify that the input is an array of two-digit integers and we need to group numbers that are permutations of each other. Use a canonical key for each number, such as sorting its digits, and count frequencies with a hash map to find the largest group size.
Pro tip: Mention that since numbers are two-digit, you can also use a fixed-size array of size 100 for counting, but a hash map is more general and still O(n). Also, discuss edge cases like empty input or numbers with repeated digits (e.g., 11).
Restate the problem: group two-digit numbers by their digit multiset and return the size of the largest group. Confirm that order of digits doesn't matter.
For each number, extract its tens and ones digits, sort them, and form a key (e.g., a string or a tuple). This key uniquely identifies the digit set.
Iterate through the array, compute the key for each number, and increment its count in a hash map. Track the maximum count seen so far.
After processing all numbers, return the maximum frequency. If the array is empty, return 0.
Time complexity is O(n) since each number is processed in constant time. Space complexity is O(k) where k is the number of distinct digit sets, at most 45 for two-digit numbers.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.