← Two Sigma Interview Insights
The setup is clean but the execution is annoying.
Start by recalling the joint distribution of the sample minimum and maximum for i.i.d. Uniform(0,1) variables, then compute the covariance using the formula Cov(X_(1), X_(n)) = E[X_(1) X_(n)] - E[X_(1)] E[X_(n)]. Derive the expectations and the product moment using order statistics properties or integration, and finally analyze the asymptotic behavior as n → ∞.
Pro tip: Emphasize that the covariance is positive but tends to zero as n grows, reflecting that extreme order statistics become independent in the limit. This demonstrates understanding of asymptotic independence and tail behavior.
State that the sample minimum X_(1) follows Beta(1, n) and the sample maximum X_(n) follows Beta(n, 1). Their means are E[X_(1)] = 1/(n+1) and E[X_(n)] = n/(n+1).
Recall that the joint density of (X_(1), X_(n)) is f(x,y) = n(n-1)(y-x)^{n-2} for 0 < x < y < 1. Use this to compute E[X_(1) X_(n)].
Evaluate the double integral E[X_(1) X_(n)] = ∫_0^1 ∫_x^1 x y n(n-1)(y-x)^{n-2} dy dx. Simplify using substitution or beta integrals to get E[X_(1) X_(n)] = 1/((n+1)(n+2)).
Plug into Cov = E[X_(1) X_(n)] - E[X_(1)]E[X_(n)] = 1/((n+1)(n+2)) - (1/(n+1))(n/(n+1)) = 1/((n+1)^2 (n+2)).
As n → ∞, the covariance decays as O(1/n^3), indicating that the minimum and maximum become asymptotically uncorrelated. Explain that this is due to the increasing independence of extreme order statistics.
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