← Snowflake Interview Insights

Snowflake·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Jun 2026

Summary

Snowflake software engineer interview with a classic sliding window problem that had a tricky follow-up tacked on at the end. Pretty standard algorithmic round but the Unicode angle threw me a bit.

Questions Asked (2)

Q1

Given a string and an integer k, find the length of the longest contiguous substring containing at most k distinct characters. Implement an O(n) sliding window solution and walk through time and space complexity.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

I got the core solution down pretty quick.

Create a free account to read the full note

AI HintsAI Generated

Suggested Approach

Use a sliding window with two pointers and a hash map to track character frequencies. Expand the right pointer to include new characters, and when the number of distinct characters exceeds k, shrink the window from the left until it's valid again. Track the maximum window length throughout.

Pro tip: Explicitly state that the algorithm runs in O(n) time because each character is added and removed at most once, and mention that the space complexity is O(k) due to the hash map storing at most k+1 distinct characters. This shows you understand the trade-offs and can analyze complexity precisely.

1. Clarify and Confirm

Restate the problem to ensure understanding: find the longest substring with at most k distinct characters. Ask about edge cases like empty string, k=0, or k >= number of distinct characters.

2. Outline Sliding Window Approach

Explain that you'll maintain a window [left, right) and a frequency map. Expand right to include new characters, and when distinct count > k, move left forward until distinct count <= k.

3. Walk Through Example

Trace the algorithm on a small example, such as 'eceba' with k=2, showing how the window expands and contracts, and how the max length is updated.

4. Analyze Complexity

State that time complexity is O(n) because each character is processed at most twice (once by right, once by left). Space complexity is O(k) for the frequency map, as it stores at most k distinct characters.

5. Discuss Edge Cases and Optimizations

Mention handling of k=0 (return 0), empty string, and possibly using an array instead of a hash map if the character set is small (e.g., ASCII).

Key Points to Mention

  • Sliding window technique with two pointers (left and right).
  • Hash map to track character frequencies and distinct count.
  • Condition to shrink window: when distinct characters exceed k.
  • Update maximum length after each valid window expansion.
  • Time complexity O(n) because each character is visited at most twice.
  • Space complexity O(k) for the frequency map, or O(1) if using a fixed-size array for ASCII.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Modify your solution to return the actual substring instead of just its length, and handle Unicode grapheme clusters correctly.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

The substring part is easy, just track the start index of the best window.

Create a free account to read the full note

AI HintsAI Generated

Suggested Approach

First, clarify the original problem (likely longest substring without repeating characters) and confirm the expected return format. Then, modify the algorithm to track start and end indices of the optimal window, and finally adapt character comparison to Unicode grapheme clusters using a library or built-in segmentation.

Pro tip: Mention that grapheme clusters can be multiple code points, so using code units (like Java's char) is incorrect; use a grapheme-aware library and consider normalization (NFC) for consistent comparison.

1. Clarify the original problem and requirements

Confirm the original problem (e.g., longest substring without repeating characters) and that the return should be the substring, not just length. Ask about Unicode handling expectations (e.g., grapheme clusters, normalization).

2. Modify algorithm to track substring boundaries

Adjust the sliding window to record the start and end indices of the longest valid substring. Update the result when a longer window is found.

3. Adapt to Unicode grapheme clusters

Replace character-based operations with grapheme cluster segmentation. Use a library (e.g., ICU, Intl.Segmenter) to iterate over grapheme clusters and treat each as a unit for uniqueness.

4. Handle normalization and edge cases

Normalize input to a consistent form (e.g., NFC) to avoid false duplicates. Consider edge cases like empty string, single grapheme, and combining characters.

5. Analyze complexity and trade-offs

Discuss time/space complexity: O(n) with sliding window, but grapheme segmentation may add overhead. Mention trade-offs between correctness and performance.

Key Points to Mention

  • Sliding window technique for longest substring without repeating characters
  • Tracking start and end indices to return the actual substring
  • Unicode grapheme clusters vs. code points vs. code units
  • Using libraries like ICU or Intl.Segmenter for grapheme segmentation
  • Unicode normalization (NFC) to handle equivalent sequences
  • Time and space complexity analysis, including overhead of grapheme handling

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.