Spent way too long trying to simulate this before realizing it's a binary search on the answer.
First, clarify the problem and constraints, then derive the feasibility condition for a target minimum value using binary search. For a given target, compute the total increments needed and check if the total decrements available (without violating positivity) can cover it, considering the increment/decrement values.
Pro tip: Mention that the answer is monotonic, so binary search is optimal, and always test edge cases like increment equals decrement or when the array has only two elements.
Confirm the operation: pick two distinct indices, add increment to one and subtract decrement from the other, ensuring all elements stay strictly positive. Restate the goal: maximize the minimum element after any number of operations.
Recognize that if a minimum value X is achievable, any value less than X is also achievable. This monotonic property allows binary search on the answer.
For a target minimum M, compute the total increments needed to raise all elements below M to at least M. Also compute the maximum total decrements that can be applied without making any element non-positive, considering the decrement value.
If the total increments needed is less than or equal to the total decrements available (adjusted by the ratio of increment to decrement), then M is feasible; otherwise, it is not.
Perform binary search over the possible range of minimum values (from 1 to max possible) using the feasibility check, and return the maximum feasible M.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.