← Meta Interview Insights

Meta·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Jun 2026

Summary

Phone screen for a software engineer role at Meta. Not much to go on from this one, just a single coding problem and that was pretty much it.

Questions Asked (1)

Q1

Validate a binary search tree.

Algorithms & Data Structures
Author's notes

Classic BST validation problem.

Create a free account to read the full note

AI HintsAI Generated

Suggested Approach

Start by clarifying the definition of a BST and edge cases, then propose an in-order traversal approach that checks if the sequence is strictly increasing. Alternatively, use a recursive approach with min/max bounds to validate each node, discussing trade-offs between time and space complexity.

Pro tip: Mention that using in-order traversal with a single previous pointer is elegant and uses O(1) extra space if you do Morris traversal, but be prepared to discuss recursion stack space. Also, emphasize that duplicates are typically not allowed in a BST, so use strict inequality.

1. Clarify the problem

Ask if the tree can contain duplicates and confirm that a BST requires left < root < right. Also, discuss edge cases like empty tree or single node.

2. Choose an approach

Decide between in-order traversal (checking for sorted order) or recursive min/max bounds. Explain why in-order is simpler and more efficient.

3. Implement the solution

Write clean code for the chosen approach. For in-order, use a recursive or iterative traversal and keep track of the previous node's value.

4. Analyze complexity

State that time complexity is O(n) since each node is visited once, and space complexity is O(h) for recursion stack (or O(1) with Morris traversal).

5. Test with examples

Walk through a few test cases: valid BST, invalid BST, tree with duplicates, and edge cases like skewed tree.

Key Points to Mention

  • In-order traversal yields sorted sequence for a valid BST.
  • Use strict inequality to handle duplicates (if not allowed).
  • Recursive min/max bounds approach is also valid but may be less intuitive.
  • Time complexity O(n) and space complexity O(h) for recursion.
  • Morris traversal can achieve O(1) space but modifies the tree temporarily.
  • Edge cases: empty tree, single node, and trees with duplicate values.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.