The interviewer nudged me toward G=2 first, which helped.
First, define the DP state and recurrence clearly, explaining how the cost of a group is computed. Then, outline the bottom-up DP implementation with O(K^2 G) time, and finally describe how to reconstruct the partition boundaries using a parent pointer array.
Pro tip: Mention that the sorted order is crucial for the contiguous grouping to be optimal, and discuss potential optimizations like divide-and-conquer DP or Knuth's optimization if the interviewer probes further.
Let dp[i][g] be the minimum cost to partition the first i documents into g groups. The recurrence is dp[i][g] = min_{j < i} (dp[j][g-1] + (i - j) * max_{j+1..i} length).
Precompute the maximum length for all contiguous subarrays to allow O(1) cost lookup, or compute on the fly using a running maximum.
Initialize dp[0][0] = 0 and others to infinity. Iterate over number of groups g from 1 to G, and for each i from 1 to K, compute dp[i][g] using the recurrence.
Maintain a parent array parent[i][g] storing the optimal j for dp[i][g]. After filling the DP table, backtrack from dp[K][G] to find the group boundaries.
State time complexity O(G K^2) and space O(G K). Mention possible optimizations like divide-and-conquer DP or Knuth's optimization if applicable.
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