The core logic clicked pretty fast but I fumbled on the edge cases.
Clarify the problem constraints and edge cases, then propose a linear scan that tracks the next expected number and compares it to each array element to identify gaps. For each gap, format it as a single number or a range, and finally check for any missing numbers after the last element up to the upper bound.
Pro tip: Mention that the solution runs in O(n) time and O(1) extra space (excluding output), which is optimal since you must examine each element. Also, handle integer overflow carefully when computing ranges, especially if lower/upper are near integer limits.
Confirm that the array is sorted, contains unique integers, and that the range is inclusive. Discuss edge cases such as empty array, no missing numbers, or missing numbers at the boundaries.
Use a linear scan with a variable 'next' initialized to 'lower'. For each number in the array, if it is greater than 'next', record the missing range from 'next' to number-1. Then set 'next' to number+1.
After processing all elements, if 'next' is less than or equal to 'upper', record the missing range from 'next' to 'upper'.
For each missing range, if the start equals the end, output the single number as a string; otherwise, output 'start->end'.
State that the time complexity is O(n) and space complexity is O(1) extra (excluding output). Discuss potential alternative approaches like binary search, but explain why linear scan is optimal here.
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