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IBM·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Jul 2026

Summary

IBM software engineer round, got a scheduling problem that I've seen floating around on leetcode for a while. Nothing too surprising but it's the kind of question where you can fumble the implementation even if you know the idea.

Questions Asked (1)

Q1

Given a list of meeting time intervals, each as a [start, end] pair, find the minimum number of conference rooms needed to accommodate all meetings simultaneously.

Algorithms & Data Structures
Author's notes

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AI HintsAI Generated

Suggested Approach

Start by clarifying the problem and edge cases, then propose an efficient algorithm such as sorting start and end times separately and using a two-pointer sweep to count concurrent meetings. Walk through a small example to validate the approach, and discuss time/space complexity.

Pro tip: Mention that the problem is equivalent to finding the maximum number of overlapping intervals, and that the sweep-line algorithm is optimal. Also, briefly discuss how to handle edge cases like empty input or zero-length meetings.

1. Clarify the problem

Ask if intervals are inclusive/exclusive, if meetings can be zero-length, and if the input is sorted. Confirm that we need the minimum number of rooms to accommodate all meetings without conflicts.

2. Choose an approach

Propose sorting start and end times separately, then using two pointers to count active meetings. Alternatively, use a min-heap to track end times of ongoing meetings.

3. Walk through an example

Demonstrate the algorithm on a small set of intervals, showing how the count of active meetings changes and how the maximum is tracked.

4. Analyze complexity

State that sorting takes O(n log n) time and the sweep takes O(n) time, leading to O(n log n) overall. Space complexity is O(n) for storing start and end arrays or the heap.

5. Discuss edge cases

Mention handling of empty input, single meeting, all meetings overlapping, and meetings that end exactly when another starts (no overlap).

Key Points to Mention

  • Sorting start and end times separately
  • Two-pointer sweep to count concurrent meetings
  • Min-heap alternative for tracking end times
  • Time complexity O(n log n) due to sorting
  • Space complexity O(n)
  • Edge cases: empty input, zero-length meetings, back-to-back meetings

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.