Spent the first few minutes trying to simulate it with a BFS and realized that could blow up badly given the constraint range goes up to 10^9.
First, clarify the problem constraints and edge cases (e.g., zero piles, negative sizes). Then, derive the necessary and sufficient condition for equality by analyzing the invariant: the total sum must be even, and the smaller pile must be able to grow to half the sum via a sequence of doublings. Finally, implement a simple check (e.g., using GCD or bitwise operations) and discuss time/space complexity.
Pro tip: Mention that this problem reduces to checking if the smaller pile can be doubled repeatedly to reach half the total, which is equivalent to the smaller pile dividing the larger pile's difference in a specific way. This shows you can spot mathematical structure quickly.
Ask about input ranges, whether piles can be zero, and if negative sizes are allowed. Confirm that moves are only legal when the giving pile has enough apples.
The total sum must be even, and the smaller pile must be less than or equal to half the sum. If not, equality is impossible.
Observe that each move doubles the receiver and subtracts from the giver, preserving the total sum. The key is whether the smaller pile can be doubled enough times to reach half the sum without exceeding it.
Show that the condition is equivalent to: let s = min(a,b), l = max(a,b). Then equality is possible iff (s + l) is even and s can be doubled to (s+l)/2, which simplifies to checking if l is a multiple of s and the quotient is a power of two.
Write a function that checks the condition in O(1) time using bitwise operations or division. Discuss time and space complexity, and test with examples.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.