My first instinct was to just use a set and call it a day, which obviously kills the order.
Start by clarifying the problem: the function should remove duplicates while preserving the original order of first occurrences. Then, present an efficient solution using a set to track seen elements and a list to build the result, and discuss time and space complexity.
Pro tip: Mention that Python 3.7+ dictionaries preserve insertion order, so `list(dict.fromkeys(lst))` is a concise and efficient one-liner. However, be prepared to explain the underlying mechanism and its O(n) complexity.
Confirm that the list can contain any hashable elements, and discuss handling of unhashable types if necessary. Ask about input size and whether the original list should be modified.
Decide between using a set for O(1) lookups or leveraging ordered dictionaries. Consider trade-offs between readability and performance.
Write clean, Pythonic code. For example, use a loop with a set, or use `dict.fromkeys` for a concise solution.
State that the time complexity is O(n) on average and space complexity is O(n) due to the additional data structures.
Walk through a few test cases, including empty list, all duplicates, and mixed types, to demonstrate correctness.
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