My first instinct was to just concatenate both lists and run a standard merge pass, which is basically right, but I fumbled the touching-endpoint condition.
Use a two-pointer technique to traverse both lists simultaneously, merging intervals on the fly. At each step, select the interval with the smaller start, then merge it with the last interval in the result if they overlap or touch; otherwise, append it. Continue until all intervals from both lists are processed.
Pro tip: Clarify upfront that intervals are closed and that touching endpoints count as overlapping, then handle edge cases like empty lists or one list being exhausted early. This shows attention to detail and prevents off-by-one errors.
Confirm that intervals are closed, sorted, and internally non-overlapping. Ask about edge cases such as empty lists or single intervals.
Set pointers i and j to the start of each list, and initialize an empty result list to store merged intervals.
While i < len(list1) and j < len(list2), pick the interval with the smaller start. If the result is empty or the picked interval does not overlap/touch the last interval in result, append it; otherwise, merge by updating the end of the last interval to the maximum of both ends.
After one list is exhausted, iterate through the remaining intervals of the other list, merging them with the last interval in result if they overlap/touch, or appending them otherwise.
Return the merged list of non-overlapping intervals.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.