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DoorDash·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Jun 2026

Summary

DoorDash software engineer round focused on a spatial lookup problem that sounds straightforward until you actually have to nail the preprocessing and complexity analysis on the spot.

Questions Asked (1)

Q1

Given N cities with unique names and (x, y) coordinates, design a system that preprocesses the data so that for any query city, you can efficiently find the nearest city sharing the same x or y coordinate. Distance is the absolute difference along the non-shared axis, with ties broken by lexicographically smaller city name. Walk through your data structures, algorithms, and the time and space complexity for both preprocessing and each query.

Algorithms & Data StructuresSystem DesignTechnical Trade-offs
Author's notes

I started with the brute force and they let me finish before asking about efficiency, which felt generous.

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AI HintsAI Generated

Suggested Approach

Clarify the problem constraints and then propose a solution using hash maps to group cities by x and y coordinates, with each group sorted by the other coordinate. For each query, perform binary search in the relevant sorted lists to find the nearest city, handling ties by comparing names. Analyze time and space complexity for preprocessing and queries.

Pro tip: Mention that you would sort each coordinate group by the secondary coordinate and city name to efficiently handle ties, and discuss potential optimizations like caching frequent queries or using balanced BSTs for dynamic updates.

1. Clarify Requirements and Constraints

Ask about input size, query frequency, whether coordinates can be negative, and if updates are needed. Confirm tie-breaking rules and distance definition.

2. Design Preprocessing Data Structures

Use two hash maps: one mapping x-coordinate to a sorted list of (y, name) for cities with that x, and similarly for y-coordinate to sorted list of (x, name). Sort each list by the secondary coordinate and then by name.

3. Query Algorithm

For a query city, look up its x in the x-map and its y in the y-map. In each sorted list, binary search for the city's secondary coordinate to find neighbors, compute distances, and select the nearest. Compare results from both maps and apply tie-breaking.

4. Complexity Analysis

Preprocessing: O(N log N) time due to sorting, O(N) space. Each query: O(log N) time for binary searches, O(1) extra space. Discuss trade-offs if using balanced BSTs for dynamic updates.

5. Discuss Extensions and Trade-offs

Mention handling multiple cities with same coordinates, potential for caching frequent queries, and scalability for large N. Consider if updates are needed and how that changes complexity.

Key Points to Mention

  • Hash maps for grouping by x and y coordinates
  • Sorting each group by the other coordinate and city name for tie-breaking
  • Binary search to find nearest neighbor in sorted lists
  • Time complexity: O(N log N) preprocessing, O(log N) per query
  • Space complexity: O(N)
  • Handling ties by lexicographically smaller city name
  • Potential optimizations for frequent queries or dynamic updates

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.