I got the general idea pretty fast, uniform region becomes a leaf, otherwise split into four quadrants and recurse.
Use a recursive divide-and-conquer strategy: for each submatrix, check if all values are the same; if so, create a leaf node, otherwise create an internal node and recurse on the four quadrants. Optimize the uniformity check with prefix sums or early termination to avoid redundant scans.
Pro tip: Clarify the node definition upfront (e.g., leaf nodes store value, internal nodes store children) and discuss trade-offs between recursion depth and iterative approaches, especially for large n. Mention that the tree depth is O(log n) and total nodes O(n^2) in the worst case.
Specify the fields: isLeaf (boolean), val (0 or 1 for leaves), and four children (topLeft, topRight, bottomLeft, bottomRight). For internal nodes, val can be arbitrary (e.g., True) and children are non-null.
Design a function that takes the matrix, current row and column offsets, and the size of the current submatrix. It returns the root node of the quad-tree for that region.
Efficiently determine if all cells in the current submatrix have the same value. Use a helper that scans the region, or precompute prefix sums for O(1) range sum queries to check if sum is 0 or area.
If uniform, return a leaf node with that value. Otherwise, split the region into four equal quadrants and recursively build child nodes, then return an internal node with those children.
Discuss time complexity: O(n^2) with prefix sums or O(n^2 log n) with naive scanning; space O(n^2) worst-case. Handle n=0 or n=1 as edge cases.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.