Recognize this as a classic binary search on the answer problem: the minimum capacity lies between the maximum package weight and the sum of all weights. For a given capacity, simulate the shipping process greedily to check if all packages can be delivered within D days. Binary search for the smallest capacity that satisfies the condition.
Pro tip: Clarify edge cases upfront, such as when D is less than the number of packages (impossible) or when D is very large (capacity equals max weight). Also, mention that the greedy simulation is optimal because any feasible schedule must load packages in order, and taking as many as possible each day never hurts.
Set low to the maximum package weight (must carry the heaviest package) and high to the sum of all weights (carry everything in one day).
Write a function that, given a capacity, simulates loading packages in order, counting days needed. Return true if days <= D.
While low < high, compute mid, check feasibility. If feasible, search left (high = mid); else search right (low = mid + 1).
Return low as the minimum capacity. Time complexity O(n log(sum - max)), space O(1).
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