I went straight for DENSE_RANK and partitioned by department, ordered by salary descending, then filtered where rank <= 3.
Use a window function like DENSE_RANK() to rank salaries within each department, then filter for ranks <= 3 and join back to the employee table to get all employees earning those salaries. This handles distinct salaries and ties correctly.
Pro tip: Clarify whether 'top 3 distinct salaries' means the three highest unique salary values (even if multiple employees share them) and whether to include ties; this shows attention to edge cases and business context.
Clarify what 'top 3 distinct salaries' means: the three highest unique salary amounts per department, and return all employees whose salary matches any of those amounts.
Use DENSE_RANK() OVER (PARTITION BY department_id ORDER BY salary DESC) to assign a rank to each distinct salary, ensuring ties get the same rank.
Select only rows where the dense rank is <= 3, which gives the top 3 distinct salaries per department.
Join the filtered result back to the employee table on department_id and salary to retrieve all employees earning those top salaries.
Write the complete SQL query, ensuring correct syntax and handling of potential NULLs or duplicates.
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