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Google·Software Engineer·Online Assessment (OA)·Junior

Junior
Apr 2026

Summary

Google SWE intern coding round with a hybrid DP problem that mashes together jump game and coin change concepts. The clarification step was apparently the whole game here.

Questions Asked (1)

Q1

Given an array where each index holds a jump length and a profit value, design an algorithm to maximize total profit by choosing which indices to 'take' (collecting the profit and jumping forward by jump_length + 1) versus skip, ending when you've passed the last index.

Algorithms & Data Structures
Author's notes

I went straight to coding without asking whether skipping costs a turn or not, and that bit me.

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AI HintsAI Generated

Suggested Approach

Clarify the problem constraints and define the state as the maximum profit achievable from each index. Use dynamic programming with memoization or bottom-up, computing dp[i] = max(profit[i] + dp[i + jump_length[i] + 1], dp[i+1]) with careful handling of out-of-bounds. Discuss time and space complexity, and consider optimizations like iterative DP or greedy if applicable.

Pro tip: Start by walking through a small example to confirm understanding and edge cases (e.g., jumps that overshoot the array). Then, explicitly state the recurrence relation before coding, and mention that you'd test with negative profits and varying jump lengths.

1. Clarify the problem

Ask about constraints: array size, profit values (can be negative?), jump lengths (can be zero?), and whether you must start at index 0. Confirm that you can choose to take or skip each index, and that taking an index forces a jump.

2. Define the DP state and recurrence

Let dp[i] be the maximum profit from index i to the end. Then dp[i] = max(dp[i+1] (skip), profit[i] + dp[i + jump_length[i] + 1] (take, if within bounds)). Base case: dp[n] = 0.

3. Choose implementation approach

Decide between top-down memoization (recursive) or bottom-up iteration. For bottom-up, iterate from the end to the start. Mention that top-down is easier to reason about but may have recursion overhead.

4. Analyze complexity and optimize

Time complexity is O(n) since each index is computed once. Space complexity is O(n) for the DP array, but can be optimized to O(1) if we only need the next few values? Actually, due to jumps, we might need to store all, but discuss.

5. Test with edge cases

Walk through examples: empty array, single element, jumps that overshoot, negative profits, and large jumps. Verify that the recurrence handles out-of-bounds correctly.

Key Points to Mention

  • Dynamic programming with optimal substructure and overlapping subproblems
  • Recurrence relation: dp[i] = max(dp[i+1], profit[i] + dp[i + jump_length[i] + 1])
  • Handling out-of-bounds indices (e.g., if i + jump_length[i] + 1 >= n, then dp[...] = 0)
  • Time complexity O(n) and space complexity O(n), with possible space optimization
  • Edge cases: negative profits, zero jump lengths, jumps that skip over the end
  • Comparison with greedy approach (which may not work due to varying jump lengths and profits)

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.