The blocking condition is what tripped me up first.
Clarify the problem by confirming that the viewing angle is centered on the observer and that trees in the same direction are blocked. Then, compute the angle of each tree relative to the observer, sort the angles, and use a sliding window to find the maximum number of unique angles within the given viewing angle.
Pro tip: Demonstrate attention to edge cases such as trees at the exact same angle (blocked) and the circular nature of angles (e.g., angles near 0 and 360 degrees). Also, discuss how to handle floating-point precision to avoid errors in angle comparisons.
Ask questions to confirm details: Is the viewing angle centered on the observer? Are trees considered points? Do trees at the same angle but different distances count as one? How to handle trees exactly on the boundary of the viewing angle?
For each tree, calculate the angle relative to the observer using atan2(dy, dx). Normalize angles to a consistent range (e.g., [0, 2π)).
Use a hash set or sort and deduplicate angles so that trees in the exact same direction are counted only once.
Sort the unique angles. Duplicate the array by adding 2π to each angle to handle circular wrap-around. Use a two-pointer sliding window to find the maximum number of angles within the viewing angle.
The size of the largest window is the answer. Discuss time complexity: O(n log n) due to sorting, and space complexity O(n).
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