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Amazon·Software Engineer·Technical Phone Screen·Intermediate

IntermediatePrefer not to say
Jun 2026Remote

Summary

Amazon SWE interview with a coding round focused on interval merging. The problem had a clean surface but a bunch of edge cases that sneak up on you if you're not careful.

Questions Asked (1)

Q1

Given an unsorted list of integer ranges as half-open intervals [start, end), merge all overlapping or directly adjacent ranges and return the merged list sorted by start, along with the total length covered.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

Sorting by start was the obvious first move and I got there quickly.

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AI HintsAI Generated

Suggested Approach

Start by sorting the intervals by their start value, then iterate through them while merging overlapping or adjacent intervals into a result list. Track the total covered length by summing the lengths of merged intervals, being careful to handle adjacency (where end == next start) as a merge condition.

Pro tip: Explicitly clarify that 'directly adjacent' means intervals like [1,3) and [3,5) should merge, and mention that you'll handle edge cases like empty input or single interval. This shows attention to detail and prevents misinterpretation.

1. Clarify requirements and edge cases

Confirm that adjacency (end == start) counts as overlap, and discuss handling of empty input, single interval, and negative numbers. This ensures alignment with the interviewer.

2. Sort intervals by start

Sort the list of intervals by their start value. This is crucial for the linear scan approach and ensures O(n log n) time complexity.

3. Merge intervals in one pass

Initialize a result list with the first interval. For each subsequent interval, if it overlaps or is adjacent to the last interval in the result (i.e., its start <= last end), merge them by updating the last interval's end to the maximum of both ends. Otherwise, add it to the result.

4. Compute total covered length

After merging, iterate through the merged intervals and sum (end - start) for each. Alternatively, accumulate the length during the merge process to avoid a second pass.

5. Return merged list and total length

Return the merged list sorted by start (which it already is) and the total length. Discuss time and space complexity: O(n log n) time due to sorting, O(n) space for the result.

Key Points to Mention

  • Sorting is necessary to achieve O(n log n) time; without sorting, the problem is more complex.
  • Adjacency condition: intervals [a,b) and [b,c) should merge into [a,c).
  • Use of a single pass after sorting to merge intervals efficiently.
  • Handling of edge cases: empty list, single interval, intervals with same start, negative values.
  • Time complexity: O(n log n) due to sorting; space complexity: O(n) for the output.
  • Potential trade-off: if the input is already sorted, we can skip sorting and achieve O(n) time.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.