I went straight for union-find and it worked, but I wasted probably five minutes convincing myself it was the right tool when BFS over adjacency would've been cleaner to explain out loud.
Model the problem as a graph where each number is a node and edges connect numbers sharing a digit. Use Union-Find (Disjoint Set Union) to efficiently merge connected components, then find the largest component size. Alternatively, build a graph of digits (0-9) and numbers, then use BFS/DFS to find connected components.
Pro tip: Clarify edge cases upfront: empty array, single element, numbers with repeated digits (e.g., 11), and numbers sharing both digits. Also discuss time/space complexity trade-offs between Union-Find and graph traversal approaches.
Confirm that connectivity is transitive and that each number is a two-digit integer (10-99). Ask about input size, possible duplicates, and whether digits can be zero (e.g., 10, 20).
Union-Find is efficient for dynamic connectivity; graph traversal (BFS/DFS) is intuitive. Consider building a bipartite graph between numbers and digits to reduce edges.
For Union-Find: initialize parent array, union numbers sharing digits, then count component sizes. For BFS/DFS: build adjacency list (or digit-to-number mapping) and traverse.
Account for empty input, single element, and numbers with identical digits. Optimize by using digit buckets (0-9) to avoid O(n^2) comparisons.
State time and space complexity (e.g., O(n α(n)) for Union-Find, O(n) for BFS with digit buckets). Walk through a small example to verify correctness.
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