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Point72·Data Scientist·Technical Phone Screen·Intermediate

Intermediate
Jun 2026

Summary

Two coding problems back to back for a Data Scientist role at Point72. The first was a k-th missing number problem and the second involved flagging redundant events inside a sliding time window. Neither felt purely DS-flavored, more like a straight SWE screen.

Questions Asked (2)

Q1

Given an unsorted array of distinct positive integers and an integer k, return the k-th smallest positive integer that does not appear in the array.

Algorithms & Data Structures
Author's notes

My first instinct was to just iterate from 1 upward and count misses, which works fine for small inputs but falls apart when nums[i] can go up to a billion.

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AI HintsAI Generated

Suggested Approach

Clarify that the array contains distinct positive integers and we need the k-th missing positive integer. Use a set for O(1) lookups and iterate from 1 upward, counting missing numbers until reaching k. Alternatively, use a boolean array of size n+k+1 to mark present numbers and scan for the k-th missing.

Pro tip: Mention that the answer is at most n+k, so you can bound your search space and avoid infinite loops. Also, discuss trade-offs: set approach uses O(n) space but is simple; boolean array is more memory-efficient for dense ranges.

1. Clarify and Restate

Confirm that the array has distinct positive integers and we need the k-th smallest positive integer not in the array. Ask about constraints (e.g., array size, k range) to determine optimal approach.

2. Choose Data Structure

Decide between using a hash set for O(1) membership checks or a boolean array of size n+k+1 to mark presence. Consider space-time trade-offs.

3. Mark Present Numbers

Iterate through the array and mark each number as present in the chosen data structure. Ignore numbers greater than n+k as they don't affect the first k missing numbers.

4. Find k-th Missing

Iterate from 1 upward, counting numbers not marked as present. When the count reaches k, return that number.

5. Analyze Complexity

State time complexity O(n + k) and space complexity O(n) or O(n+k) depending on approach. Discuss potential optimizations like using the array itself for marking if modification is allowed.

Key Points to Mention

  • The answer is bounded by n + k, so we only need to consider numbers up to that.
  • Using a hash set gives O(n) time and O(n) space, but a boolean array can be more efficient for dense ranges.
  • We can ignore numbers greater than n+k because they cannot be among the first k missing positives.
  • If the array can be modified, we can use cyclic sort or in-place marking to achieve O(n) time and O(1) extra space.
  • Edge cases: k=0? (usually k>=1), empty array, array containing all numbers from 1 to n.
  • The problem is similar to 'First Missing Positive' but generalized to k-th missing.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Given parallel arrays of operation names and timestamps, and a window size W, count how many events are redundant, where an event is redundant if the same operation has occurred at least twice within the preceding W seconds.

Algorithms & Data StructuresProduct Analytics & Metrics
Author's notes

Sliding window with a per-operation deque tracking the last two timestamps.

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AI HintsAI Generated

Suggested Approach

Clarify the problem definition and edge cases, then propose an efficient algorithm using a hash map to track the last occurrence of each operation. Iterate through the events in chronological order, and for each event, check if the same operation occurred within the previous W seconds; if so, increment the redundant count and update the last occurrence time.

Pro tip: Emphasize that the solution should handle large datasets efficiently, ideally O(n) time and O(k) space where k is the number of unique operations. Also, discuss how to handle ties or out-of-order timestamps if the input isn't sorted.

1. Clarify the problem

Ask questions to confirm the definition of 'redundant', whether the arrays are sorted by timestamp, and what to do if multiple events occur at the same timestamp.

2. Choose data structures

Select a hash map to store the most recent timestamp for each operation, enabling O(1) lookups. If timestamps are not sorted, consider sorting first or using a sliding window approach.

3. Design the algorithm

Iterate through the events, and for each event, check if the operation's last occurrence is within W seconds. If yes, mark as redundant; then update the last occurrence to the current timestamp.

4. Analyze complexity

State the time complexity (O(n) if sorted, O(n log n) if sorting needed) and space complexity (O(k) for k unique operations).

5. Test with examples

Walk through a small example to verify correctness, including edge cases like no redundancies, all redundancies, and boundary conditions (exactly W seconds apart).

Key Points to Mention

  • Hash map for last occurrence tracking
  • Time and space complexity analysis
  • Handling of unsorted timestamps
  • Definition of 'within W seconds' (inclusive/exclusive)
  • Edge cases: empty input, single event, multiple operations
  • Scalability for large datasets

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.