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AkunaCapital·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
May 2026

Summary

Akuna Capital software engineer interview with a coding problem that looks simple on the surface but has a few layers worth thinking through. Pretty standard algo round vibe.

Questions Asked (1)

Q1

Given a list of strings, remove any string that is an anagram of a string appearing earlier in the list, then return the remaining strings in lexicographic order.

Algorithms & Data Structures
Author's notes

My first instinct was to sort each string's characters and use that as a key in a set, which works fine.

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AI HintsAI Generated

Suggested Approach

Clarify the problem constraints (e.g., case sensitivity, input size) and then propose an efficient solution using a hash set to track canonical forms of anagrams. For each string, compute its canonical form (e.g., sorted characters) and check if it's already seen; if not, add it to the result and mark the canonical form as seen. Finally, sort the result lexicographically.

Pro tip: Mention that the canonical form can be a sorted string or a character count signature, and discuss the trade-offs (e.g., sorting is O(k log k) per string, counting is O(k) but may use more space). This shows awareness of optimization.

1. Clarify requirements and edge cases

Ask about case sensitivity, whether strings can be empty, and if the input list can be modified. Confirm that 'earlier' means original order.

2. Choose canonical representation

Decide on a method to identify anagrams: sorting characters or using a character frequency tuple. Consider time/space trade-offs.

3. Iterate and filter

Traverse the list in order, compute the canonical form for each string, and use a hash set to track seen forms. Keep only strings whose form is new.

4. Sort and return

Collect the kept strings and sort them lexicographically (using the language's default string comparison) before returning.

5. Analyze complexity

State the time complexity: O(n * k log k) for sorting each string, plus O(n log n) for final sort, where n is number of strings and k is max length. Space complexity O(n * k) for storing canonical forms.

Key Points to Mention

  • Use a hash set to track canonical forms for O(1) average lookup.
  • Canonical form can be sorted string or character count signature; discuss trade-offs.
  • Preserve original order when determining which string to keep (first occurrence).
  • Final sorting is lexicographic, which may differ from original order.
  • Edge cases: empty strings, strings with same characters but different lengths (impossible for anagrams), and case sensitivity.
  • Time and space complexity analysis.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.