Spent probably 10 minutes trying to think about greedy subarray coverage before I realized you don't need to simulate anything.
First, clarify that the goal is to make the array non-decreasing by only adding positive integers to contiguous subarrays, and that we want to minimize the total added sum. Then, derive the optimal strategy: for each position where the array decreases, add the difference to the suffix starting at that position, which is equivalent to setting each element to the running maximum of the original array. Finally, compute the total added sum as the sum of (running maximum - original value) for each element.
Pro tip: Mention that the optimal solution is to make each element equal to the maximum of all previous elements, and that the total added sum is simply the sum of differences between the running maximum and the original array. This shows you understand the greedy nature and can reduce the problem to a simple O(n) computation.
Restate the problem: we can only add positive integers to contiguous subarrays, and the final array must be non-decreasing. We need to minimize the total sum of additions.
Observe that to make the array non-decreasing, each element must be at least as large as the previous element. The minimal way is to set each element to the maximum of all elements up to that point (the running maximum).
Argue that any valid final array must have each element >= the running maximum of the original array, so the minimal total addition is achieved by setting each element exactly to the running maximum.
Iterate through the array, keep track of the running maximum, and sum the differences between the running maximum and the original element. This gives the minimal total sum of additions.
The algorithm runs in O(n) time and O(1) extra space. Handle edge cases like already non-decreasing arrays (sum = 0) and arrays with negative numbers (running maximum may be negative, but additions are still positive).
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.