← Molocoads Interview Insights
My first instinct was just brute force every pair and track the max prefix length.
Clarify the problem constraints and edge cases, then propose an efficient algorithm. A trie-based approach can find the maximum LCP by inserting all strings from one list and querying with strings from the other, but also consider sorting and binary search as alternatives. Discuss time/space complexity and trade-offs.
Pro tip: Mention that you can optimize by only considering strings that share the first character, and if the lists are large, a trie is more efficient than pairwise comparison. Also, handle empty strings and no common prefix gracefully.
Ask about constraints: list sizes, string lengths, character set, and whether empty strings are allowed. Confirm that you need the maximum LCP over all pairs (one from each list).
Mention that comparing all pairs takes O(|A|*|B|*L) time, which is inefficient for large inputs. This sets the stage for optimization.
Describe a trie-based solution: insert all strings from the smaller list into a trie, then for each string in the other list, traverse the trie to find the longest common prefix. Alternatively, sort both lists and use binary search or two pointers to find the maximum LCP.
For trie: O((|A|+|B|)*L) time and O(|A|*L) space. For sorting: O(|A|log|A| + |B|log|B|) time and O(1) extra space. Discuss which is better based on constraints.
Cover cases like empty lists, empty strings, no common prefix, and very long strings. Summarize the chosen approach and why it's optimal.
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