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The merge part I had down pretty quickly, two pointers, advance whichever side is smaller, done.
Start by clarifying the problem constraints (e.g., sorted ascending, duplicates within each array, output format) and then propose a two-pointer approach that merges while skipping duplicates. Walk through a small example to illustrate, then analyze time and space complexity, mentioning edge cases and potential optimizations.
Pro tip: Explicitly state that you would handle duplicates by comparing the current element with the last added element in the result, and mention that if the arrays are very large, you might consider a streaming approach to avoid storing the entire output in memory.
Ask about input size, whether arrays are sorted ascending or descending, if duplicates exist within each array, and the expected output format (e.g., new array, in-place, or stream).
Explain that you will use two pointers, one for each array, to traverse them in order, comparing elements and advancing the pointer of the smaller element.
Describe how to skip duplicates by checking if the current element equals the last added element in the result, and only adding if it's different.
Choose a small example with duplicates (e.g., [1,3,5] and [2,3,6]) and step through the algorithm to demonstrate correctness.
State that time complexity is O(m+n) and space complexity is O(m+n) for the output (or O(1) extra if done in-place with one array having extra space). Mention edge cases like empty arrays, all duplicates, or one array exhausted early.
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