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Goldman Sachs·Software Engineer·Online Assessment (OA)·Intermediate

Intermediate
Apr 2026

Summary

Two coding problems for a Goldman Sachs SWE round, both pretty self-contained but the second one had some sneaky edge cases worth thinking through before you dive in.

Questions Asked (2)

Q1

Given a string of lowercase letters, find the index of the first character that appears exactly once. Return -1 if none exists.

Algorithms & Data Structures
Author's notes

Pretty standard frequency map problem.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the problem constraints (e.g., string length, character set) and then propose an efficient solution using a hash map to count character frequencies in one pass, followed by a second pass to find the first character with count 1. Discuss time and space complexity, and consider edge cases like empty string or all repeating characters.

Pro tip: Mention that you can optimize space by using a fixed-size array of 26 integers for lowercase letters, and that the two-pass approach is optimal because you must see all characters before knowing which are unique.

1. Clarify requirements and constraints

Ask about input size, character set (e.g., only lowercase letters), and expected output format. Confirm whether the string can be empty or contain non-lowercase characters.

2. Outline a brute-force approach

Briefly mention that a naive solution would check each character against all others, resulting in O(n^2) time, which is inefficient for large inputs.

3. Propose an optimal hash map solution

Explain that you can use a hash map (or array of size 26) to count occurrences of each character in one pass, then iterate through the string again to find the first character with count 1.

4. Analyze complexity and edge cases

State that time complexity is O(n) and space complexity is O(1) for fixed alphabet. Discuss edge cases: empty string returns -1, no unique character returns -1, and all characters unique returns index 0.

5. Implement and test

Write clean code with meaningful variable names, and walk through a few test cases (e.g., 'leetcode' returns 0, 'loveleetcode' returns 2, 'aabb' returns -1) to verify correctness.

Key Points to Mention

  • Time complexity: O(n) for two passes, which is optimal.
  • Space complexity: O(1) if using fixed-size array for lowercase letters, or O(k) for hash map where k is unique characters.
  • Two-pass approach: first pass to count frequencies, second pass to find first unique.
  • Edge cases: empty string, no unique character, all characters unique.
  • Alternative: use an array of size 26 for constant space and faster access.
  • Clarify that 'first' means earliest index in the original string.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Given a list of student ID and score pairs where a student can appear multiple times, compute each student's average score and return the highest average across all students.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

This one felt simple but I spent probably two minutes just asking clarifying questions about rounding and whether ties needed to return the student ID too.

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AI HintsAI Generated

Suggested Approach

Clarify the input format and constraints, then propose a hash map solution that accumulates sum and count per student in one pass, computing averages and tracking the maximum. Discuss time and space complexity, and consider edge cases like empty input or negative scores.

Pro tip: Mention that you would handle ties or missing data explicitly, and note that a single-pass approach is optimal for large datasets, showing awareness of scalability and data integrity.

1. Clarify requirements and constraints

Ask about input size, data types, whether scores can be negative, and if the list is sorted. Confirm expected output format (e.g., return the highest average value or the student ID).

2. Choose data structures

Use a hash map (dictionary) to store per-student sum and count, enabling O(1) updates. Alternatively, store a list of scores per student, but that uses more memory.

3. Design the algorithm

Iterate through the list once, updating each student's sum and count. Then iterate over the map to compute averages and track the maximum. This is O(n) time and O(k) space, where k is the number of unique students.

4. Handle edge cases

Consider empty input (return null or throw exception), students with no scores (should not occur if every entry has a score), and negative scores (average can be negative).

5. Analyze trade-offs and optimize

Discuss whether to compute averages on the fly or after accumulation. Mention that if the list is huge and memory is a concern, a streaming approach with a map is still optimal. Also consider if multiple passes are acceptable.

Key Points to Mention

  • Hash map for O(1) updates of sum and count per student
  • Single-pass accumulation for efficiency
  • Time complexity O(n) and space complexity O(k)
  • Edge cases: empty input, negative scores, ties
  • Clarifying questions about input format and expected output
  • Trade-offs between storing sum/count vs. list of scores

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.