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Meta·Software Engineer·Technical Phone Screen·Intermediate

IntermediatePrefer not to say
May 2026Remote

Summary

Meta SWE coding round, one algorithmic question about frequency counting with a constraint that made it slightly more interesting than it sounds.

Questions Asked (1)

Q1

Given an array of integers and a number k, return the k most frequent elements. You can't use any built-in frequency shortcut methods.

Algorithms & Data Structures
Author's notes

The no-most_common constraint is what trips people up here.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the problem constraints (e.g., input size, uniqueness of answer, k validity). Then propose a two-step solution: first compute frequencies using a hash map, then select the top k using a min-heap of size k or bucket sort for O(n) time. Discuss trade-offs between approaches and analyze time/space complexity.

Pro tip: Mention that you would avoid sorting all unique elements (O(n log n)) by using a heap or bucket sort, and explicitly state that you're not using built-in frequency shortcuts like collections.Counter. This shows awareness of both efficiency and the constraint.

1. Clarify requirements and constraints

Ask about input size, range of integers, whether k is always valid, and if the answer order matters. Confirm that built-in frequency shortcuts are disallowed.

2. Compute frequencies manually

Use a hash map (dictionary) to count occurrences of each element by iterating through the array. This is O(n) time and O(n) space.

3. Select top k frequent elements

Choose an efficient selection method: either use a min-heap of size k (O(n log k)) or bucket sort by frequency (O(n)). Explain why this avoids full sorting.

4. Analyze complexity and edge cases

State time and space complexity for your chosen approach. Discuss edge cases like k=1, k=number of unique elements, or empty array.

5. Test with examples

Walk through a small example to verify correctness, such as array [1,1,1,2,2,3] and k=2, showing the frequency map and final output.

Key Points to Mention

  • Hash map for frequency counting without built-in shortcuts
  • Min-heap of size k for O(n log k) time, or bucket sort for O(n) time
  • Time and space complexity analysis
  • Handling edge cases: k=1, k=unique count, empty input
  • Trade-offs between heap and bucket sort approaches
  • Avoiding full sort to achieve better than O(n log n) time

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.