The 300-second sliding window is the crux of it.
Clarify that hits arrive in chronological order, then propose a queue-based solution where each hit is stored with its timestamp. For getHits, remove hits older than timestamp - 300 and return the queue size, achieving O(1) amortized time per operation.
Pro tip: Mention that since timestamps are monotonically increasing, you can use a queue (or circular buffer) to avoid scanning all hits; this shows you understand the problem's constraints and can optimize for real-world scenarios.
Confirm that hits arrive in chronological order, that the window is exactly 300 seconds (inclusive), and that multiple hits can have the same timestamp. Ask about expected hit rate and memory constraints.
Select a queue (e.g., deque) to store timestamps of hits, because it supports O(1) append and popleft operations. Alternatively, consider a circular buffer if the maximum number of hits per window is known.
Append the timestamp to the queue. Optionally, if using a fixed-size array, maintain a head index and overwrite old entries.
While the queue is not empty and the front timestamp is <= timestamp - 300, remove it. Then return the queue size. This ensures only hits within the last 300 seconds are counted.
State that each hit is added once and removed at most once, giving O(1) amortized time per operation and O(n) space where n is the number of hits in the window. Discuss edge cases like no hits, all hits expired, and boundary timestamps.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.