My first instinct was just k/N and I almost said it out loud.
Recognize that the number of meetings in Room 1 follows a Binomial(k, 1/N) distribution. Use the conditional expectation formula E[X | X ≥ 1] = E[X] / P(X ≥ 1) = (k/N) / (1 - (1 - 1/N)^k).
Pro tip: Clearly state the distributional assumption (independent, uniformly random assignment) and then apply the conditional expectation formula. This shows you can translate a word problem into a probabilistic model and handle conditioning rigorously.
Let X be the number of meetings assigned to Room 1. Assume each meeting is independently assigned to one of N rooms with equal probability 1/N.
X follows a Binomial distribution with parameters k (number of trials) and p = 1/N (probability of success). So X ~ Binomial(k, 1/N).
The expected number of meetings in Room 1 without any condition is E[X] = k * (1/N) = k/N.
The probability that Room 1 has at least one meeting is P(X ≥ 1) = 1 - P(X = 0) = 1 - (1 - 1/N)^k.
Using E[X | X ≥ 1] = E[X] / P(X ≥ 1), the expected number of meetings in Room 1 given at least one is (k/N) / (1 - (1 - 1/N)^k).
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