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LinkedIn·Software Engineer·Technical Phone Screen·Intermediate

IntermediatePrefer not to say
Jun 2026

Summary

Got a coding question from LinkedIn that looked straightforward on the surface. Bracket matching is a classic and I'd seen it before, but the pressure of an actual interview made me second-guess my stack-based approach more than I should have.

Questions Asked (1)

Q1

Given a string containing only bracket characters, write a function to determine whether the string is valid. A valid string requires every opening bracket to be closed by the same type and in the correct order.

Algorithms & Data Structures
Author's notes

I knew to use a stack the second I read it, but I fumbled explaining why for a bit.

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AI HintsAI Generated

Suggested Approach

Clarify the bracket types and edge cases, then propose a stack-based solution that pushes opening brackets and pops for closing brackets, ensuring matches. Walk through an example and analyze time and space complexity.

Pro tip: Mention that you'd handle edge cases like empty string and odd length early, and discuss how to extend the solution to support additional bracket types or streaming input.

1. Clarify requirements

Ask which bracket types are included (e.g., (), [], {}) and confirm that an empty string is considered valid. Also clarify if the input can be null or contain non-bracket characters.

2. Choose data structure

Select a stack to track opening brackets, as it naturally handles the LIFO order required for matching brackets.

3. Design algorithm

Iterate through each character: if it's an opening bracket, push it onto the stack; if it's a closing bracket, check if the stack is non-empty and the top matches the corresponding opening bracket, then pop. After iteration, the stack must be empty.

4. Handle edge cases

Check for empty string (return true), odd length (return false), and null input (return false or throw exception based on requirements). Also handle mismatched brackets and extra closing brackets.

5. Analyze complexity

State that the time complexity is O(n) since each character is processed once, and space complexity is O(n) in the worst case (e.g., all opening brackets).

Key Points to Mention

  • Use a stack to track opening brackets.
  • Map closing brackets to their corresponding opening brackets for easy comparison.
  • Check for empty stack when encountering a closing bracket.
  • Ensure the stack is empty after processing all characters.
  • Time complexity: O(n), space complexity: O(n).
  • Consider edge cases: empty string, odd length, null input, and non-bracket characters.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.