Start by clarifying the problem and constraints, then propose an optimal two-pointer solution that aligns the lists by length difference and traverses to find the intersection. Implement in C++ using raw pointers, and discuss trade-offs with shared_ptr and complexity.
Pro tip: Emphasize that the lists must remain unmodified, so avoid tricks like reversing or marking nodes; instead, use length difference or cycle detection. Also, mention that shared_ptr is unsuitable due to ownership semantics and overhead.
Ask if the lists are singly linked, if they intersect by node reference (not value), and if modification is allowed. Confirm that intersection means sharing the same node, not just same value.
Explain the two-pointer technique: compute lengths, advance the longer list's pointer by the difference, then move both pointers until they meet or reach null. This gives O(m+n) time and O(1) space.
Write clean code using raw pointers (Node*). Handle edge cases: empty lists, no intersection, intersection at head. Avoid modifying the lists.
Compare raw pointers vs shared_ptr: raw pointers are lightweight and standard for such algorithms, while shared_ptr adds overhead and ownership complexity. Mention that shared_ptr could be used if the lists are managed by shared ownership, but it's not ideal for this problem.
State time O(m+n) and space O(1). Walk through test cases: no intersection, intersection at different positions, one list empty.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.