The example looks simple enough until you actually sit down to implement it.
Use a BFS traversal while tracking each node's horizontal distance (column index) from the root. Store nodes in a hash map keyed by column, then sort the columns and output the values in order.
Pro tip: Mention that BFS naturally preserves top-to-bottom order within each column, and for columns with the same horizontal distance, nodes are visited left-to-right due to the queue order. Also, note that using a TreeMap can avoid explicit sorting.
Assign the root column index 0. For each left child, decrement the parent's column index by 1; for each right child, increment by 1.
Perform a BFS (level-order) traversal using a queue. Store pairs of (node, column index) in the queue.
Use a hash map (or TreeMap) to map each column index to a list of node values. Append values as nodes are dequeued.
If using a hash map, sort the keys (column indices) in ascending order. Then output the lists of values for each column in that order.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.