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Citadel·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Jun 2026

Summary

Citadel software engineer interview with a string manipulation problem that's trickier than it looks. The palindrome constraint combined with the periodicity constraint means you have to think carefully about which character positions are actually linked together.

Questions Asked (1)

Q1

Given a string of length N and an integer k where k divides N evenly, find the minimum number of character substitutions needed so that the resulting string is both a palindrome and k-periodic (meaning every character equals the one k positions ahead of it).

Algorithms & Data Structures
Author's notes

The two constraints interact in a non-obvious way.

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AI HintsAI Generated

Suggested Approach

Model the constraints as a graph where each position is a node, and edges connect positions that must have the same character due to the palindrome and k-periodic conditions. Find connected components, then for each component determine the most frequent character and count substitutions needed. Sum over all components to get the minimum total substitutions.

Pro tip: Clarify that the constraints are independent and can be combined into a single union-find structure; this avoids double-counting and ensures optimality. Also, mention that the time complexity is O(N * alphabet_size) or O(N) with frequency counting, which is efficient for large N.

1. Understand the constraints

Restate that the string must be a palindrome (s[i] = s[N-1-i]) and k-periodic (s[i] = s[i+k] for all valid i). Note that k divides N evenly.

2. Build equivalence classes

Use union-find (or graph traversal) to group positions that must have the same character. For each i, union i with N-1-i and with i+k (if i+k < N).

3. Find optimal character per component

For each connected component, count the frequency of each character (a-z). The optimal character is the one with the highest frequency; the number of substitutions needed is the component size minus that frequency.

4. Sum substitutions

Sum the substitutions over all components to get the minimum total number of character changes required.

5. Analyze complexity

Explain that with union-find, the time is nearly O(N α(N)) plus O(N * 26) for frequency counting, which is effectively O(N). Space is O(N).

Key Points to Mention

  • Union-Find (Disjoint Set Union) for efficiently grouping positions with equality constraints.
  • The constraints form a graph where each connected component must be assigned a single character.
  • For each component, choose the character that appears most frequently to minimize substitutions.
  • The total minimum substitutions is the sum over components of (component size - max frequency).
  • Time complexity: O(N α(N) + 26N) ≈ O(N), space O(N).
  • Edge cases: k=1 (all characters must be same), k=N (only palindrome constraint), and handling of 0-indexed vs 1-indexed positions.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.