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Meta·Software Engineer·Onsite - Coding / Algorithms·Intermediate

Intermediate
Apr 2026

Summary

Meta software engineer coding round, two questions back to back. Nothing too wild but the tree traversal caught me more off guard than it should have.

Questions Asked (2)

Q1

Solve a sliding window problem such as finding the longest substring without repeating characters.

Algorithms & Data Structures
Author's notes

Knew the pattern going in, which helped.

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AI HintsAI Generated

Suggested Approach

Start by clarifying the problem and walking through a brute-force solution to establish a baseline. Then introduce the sliding window technique, explaining how two pointers and a hash map can track characters and their indices to efficiently find the longest substring without repeats. Finally, analyze time and space complexity and test with edge cases.

Pro tip: At Meta, interviewers value clean, bug-free code and the ability to explain your thought process. Practice articulating your approach before coding, and always consider edge cases like empty strings or all unique characters.

1. Clarify and Confirm

Ask clarifying questions to ensure you understand the problem constraints (e.g., character set, string length, expected output). Confirm with the interviewer before proceeding.

2. Discuss Brute Force

Briefly describe a naive solution (e.g., check all substrings) and its O(n^3) or O(n^2) complexity to show you can think of a baseline.

3. Introduce Sliding Window

Explain the sliding window approach: use two pointers (left and right) to represent a window, and a hash map to store the last seen index of each character. Expand right, and when a duplicate is found, move left to the right of the previous occurrence.

4. Code and Test

Write clean code with meaningful variable names. Walk through a small example to verify correctness, and test edge cases like empty string, single character, and all unique characters.

5. Analyze Complexity

State that the time complexity is O(n) since each character is visited at most twice, and space complexity is O(min(n, m)) where m is the size of the character set.

Key Points to Mention

  • Sliding window technique with two pointers
  • Hash map to store character indices for O(1) lookups
  • Time complexity O(n) and space complexity O(min(n, m))
  • Handling edge cases (empty string, all unique, all same)
  • Comparison with brute force to highlight efficiency
  • Potential optimizations like using an array for ASCII characters

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Given a binary tree, return the values of each level as a list of lists (level order traversal).

Algorithms & Data Structures
Author's notes

I default to DFS for tree stuff so my brain stalled for a second before I remembered BFS is the cleaner fit here.

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AI HintsAI Generated

Suggested Approach

Clarify the problem and edge cases, then propose a BFS using a queue to process nodes level by level. For each level, record the current queue size to process exactly that many nodes, collecting their values and enqueuing children. Analyze time and space complexity, and discuss potential optimizations or alternative approaches like DFS with level tracking.

Pro tip: At Meta, interviewers value clean, bug-free code and strong communication. Before coding, walk through a small example to confirm understanding, and after coding, test with edge cases like an empty tree or a skewed tree. Mention that BFS is optimal for level order, but DFS can also work if you track depth, showing versatility.

1. Clarify requirements and edge cases

Ask if the tree can be empty, if node values are unique, and if the output should be a list of lists. Confirm that levels are processed from left to right.

2. Choose BFS with a queue

Explain that BFS naturally processes nodes level by level. Use a queue to store nodes; for each level, determine the number of nodes to process and collect their values.

3. Implement the algorithm

Initialize a queue with the root. While the queue is not empty, get the current level size, iterate that many times, dequeue nodes, add their values to a level list, and enqueue their children. Append the level list to the result.

4. Analyze complexity and test

State that time complexity is O(n) and space complexity is O(n) in the worst case (e.g., a full level). Walk through a small example and test edge cases like empty tree, single node, and skewed tree.

5. Discuss alternatives and optimizations

Mention that DFS with a depth parameter can also solve this, but BFS is more intuitive. If asked, discuss how to handle very large trees or memory constraints.

Key Points to Mention

  • BFS uses a queue to process nodes level by level.
  • Track the size of the queue at the start of each level to separate levels.
  • Time complexity is O(n) where n is the number of nodes.
  • Space complexity is O(n) for the queue, which can hold up to the maximum number of nodes at any level.
  • Edge cases: empty tree returns an empty list; a tree with only a root returns [[root.val]].
  • Alternative: DFS with level tracking can also produce level order, but BFS is more straightforward.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.