The base case wasn't bad, just transpose and reverse logic, but I fumbled the follow-up.
Start by clarifying the problem and edge cases, then propose a straightforward solution using extra space, and finally discuss the in-place O(1) space approach for square matrices, explaining why it doesn't generalize to non-square matrices. Emphasize the trade-offs between simplicity and space efficiency.
Pro tip: Demonstrate awareness that the in-place rotation is only possible for square matrices, and for non-square matrices, O(1) extra space is impossible without overwriting data. This shows deep understanding of the problem constraints.
Ask about matrix dimensions, data types, and whether the rotation should be in-place or can return a new matrix. Discuss edge cases like empty matrix, 1x1, 1xN, Nx1.
Create a new matrix of size m x n and map each element (i, j) to (j, n-1-i) in the new matrix. This is O(n*m) time and O(n*m) space.
For square matrices (n x n), rotate in-place by first transposing the matrix and then reversing each row. This uses O(1) extra space.
For non-square matrices, the dimensions change (n x m becomes m x n), so the original matrix cannot hold the result without overwriting. Thus, O(1) extra space is impossible unless we allow modifying the input in a destructive way that loses data.
Compare the simple approach (easy, uses extra space) with the in-place approach (space-efficient but only for square matrices). Mention that for non-square, extra space is necessary.
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