← Squarepoint Interview Insights
I saw max-heap pretty quickly, always pull the largest quantity, sell it, push quantity minus one back in.
Recognize that to maximize revenue, you should always sell the product with the highest current stock (which equals its price). Use a max-heap to efficiently extract the maximum, sell one unit, decrement its quantity, and reinsert if still positive. Repeat for m customers, summing the revenues.
Pro tip: Discuss the greedy choice and its proof: selling the highest-priced item first is optimal because it reduces the price of that item for future sales, but any other choice would yield less immediate revenue and cannot lead to a better future since prices only decrease. Also mention the time complexity O((n + m) log n) and potential optimizations like early termination if all stocks are zero.
Clarify that each product's price equals its current stock, and each sale reduces that stock by 1, earning the pre-decrement price. The goal is to maximize total revenue from m sales.
Argue that selling the product with the highest current stock (price) first is optimal, as it yields the maximum immediate revenue and any alternative would give less now and cannot improve future revenues because prices only decrease.
Use a max-heap (priority queue) to efficiently retrieve and update the maximum stock. Initialize the heap with all positive stock quantities.
For each of the m customers: extract the max, add it to total revenue, decrement it by 1, and if still positive, reinsert into the heap. If the heap is empty, stop early.
Time complexity is O((n + m) log n) due to heap operations. Space is O(n). Handle cases where m exceeds total stock, or all stocks are zero initially.
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