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I jumped straight to Gauss summation and got it working, sum of L to R minus the actual array sum gives you the answer, O(n) time O(1) space.
Start by clarifying the problem constraints (e.g., array size, range, duplicates, integer overflow) and then present multiple approaches: brute force, mathematical sum, binary search, and XOR. Compare their time/space complexities and discuss trade-offs, ultimately recommending the optimal solution based on constraints.
Pro tip: Mention that binary search can be adapted to find the missing number in O(log n) time by comparing the middle element's value to its expected value, and highlight that this approach avoids integer overflow issues present in the sum method.
Ask about the array size, range [L, R], whether duplicates exist, and if the array is sorted in ascending order. Confirm that exactly one number is missing and all others appear once.
Describe a linear scan to find the first gap (O(n)) and the sum formula (expected sum minus actual sum) which is O(n) time and O(1) space but may overflow for large ranges.
Explain that since the array is sorted, we can binary search for the missing number by checking if the middle element equals its expected value (L + index). If it does, the missing number is to the right; otherwise, it's to the left.
Mention that XOR of all expected numbers and array elements gives the missing number in O(n) time and O(1) space without overflow, but it's not as efficient as binary search for large n.
Summarize time/space complexities: brute force O(n), sum O(n) with overflow risk, XOR O(n) no overflow, binary search O(log n). Recommend binary search as optimal for sorted arrays, but note that if the array is unsorted, XOR or sum is better.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.