Dry-running through an example was basically all they wanted.
Clarify the problem constraints and edge cases, then discuss the sweep line algorithm using a min-heap to track end times. Alternatively, present the two-pointer approach with sorted start and end times, and analyze time/space complexity.
Pro tip: Mention that the problem is equivalent to finding the maximum number of overlapping intervals at any point, and that the heap approach naturally handles the Meeting Rooms III variant where rooms are assigned to meetings with the earliest end time.
Ask about input format, whether intervals are inclusive/exclusive, if meetings can be back-to-back, and if the number of rooms is fixed (Meeting Rooms III).
Briefly mention a simple O(n^2) approach that checks each meeting against all others to count overlaps, to establish a starting point.
Sort meetings by start time, use a min-heap to track end times of ongoing meetings, and for each meeting, remove ended meetings and add the new end time; the heap size is the room count.
Sort start and end times separately, use two pointers to count active meetings, incrementing on start and decrementing on end, tracking the maximum.
State time O(n log n) and space O(n), and explain how to adapt for Meeting Rooms III (e.g., using a priority queue of rooms by end time and room number).
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