← Sumo Logic Interview Insights
Looked straightforward until I started thinking about what 'different URL' actually means per user across both lists.
Clarify the problem: each list contains (user, URL) pairs for a day; find users present in both lists with different URLs. Use a hash map to store user→URL from the first list, then iterate the second list to check for matching users with different URLs, collecting results. Discuss time/space complexity and edge cases like duplicate entries.
Pro tip: Mention that if a user appears multiple times in a day, you need to decide how to handle it—e.g., consider all visits or just the first/last. This shows attention to real-world data ambiguity and can lead to a more robust solution.
Confirm the input format: each list contains (user, URL) pairs. Ask if a user can appear multiple times in a day and how to handle that. Define output: list of users or count.
Use a hash map (dictionary) to map user to URL from the first list. This allows O(1) average lookup when processing the second list.
Iterate through the first list and populate the hash map. If duplicates exist, decide on a rule (e.g., keep first, last, or store a set of URLs).
Iterate through the second list. For each (user, URL), check if the user exists in the map and if the URL differs. If so, add the user to the result set.
State time complexity O(n+m) and space O(n). Discuss edge cases: empty lists, no common users, same URL, duplicate users, and large data.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.