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Uber·Data Scientist·Technical Phone Screen·Intermediate

IntermediatePrefer not to say
Jun 2026

Summary

Uber data scientist interview with a coding question that looked deceptively simple. The palindrome problem had more edge cases than I expected and I fumbled through a couple of them live.

Questions Asked (1)

Q1

Given a positive integer n, find the smallest integer strictly greater than n that is a palindrome (no leading zeros allowed).

Algorithms & Data Structures
Author's notes

I started with the obvious cases and worked inward.

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AI HintsAI Generated

Suggested Approach

Start by clarifying edge cases and constraints, then propose a solution that constructs the next palindrome rather than brute-force checking each number. Discuss how to handle carries and ensure the result is strictly greater than n, with no leading zeros.

Pro tip: Mention that a naive increment-and-check approach is O(n) in the worst case and may be too slow for large n, so an O(d) construction (where d is the number of digits) is preferred. Also, highlight that you would test edge cases like n=9, n=99, n=123, and n=9999.

1. Clarify requirements and edge cases

Confirm that n is positive, no leading zeros, and the result must be strictly greater. Discuss examples like n=9 -> 11, n=99 -> 101, n=123 -> 131.

2. Choose an efficient algorithm

Decide between brute-force and constructive approach. Explain that constructing the next palindrome by mirroring the left half is O(d) and more efficient.

3. Outline the construction steps

Describe how to split the number into left half, mirror it to form a palindrome, and if it's not greater than n, increment the left half and re-mirror, handling carries and digit growth.

4. Handle special cases

Address cases where incrementing causes a carry that increases the number of digits (e.g., 999 -> 1001) and ensure no leading zeros.

5. Analyze complexity and test

State time and space complexity (O(d) time, O(d) space) and walk through test cases to validate correctness.

Key Points to Mention

  • Brute-force is O(n) and inefficient for large n; constructive approach is O(d).
  • Mirroring the left half to form a palindrome and checking if it's greater than n.
  • Incrementing the left half when the mirrored palindrome is not greater, with carry propagation.
  • Handling digit growth (e.g., 999 -> 1001) and ensuring no leading zeros.
  • Edge cases: single-digit numbers, numbers like 9, 99, 999, and numbers with even/odd digit lengths.
  • Time and space complexity analysis.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.