← Amazon Interview Insights

Amazon·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Jun 2026

Summary

Amazon SWE coding round, just one question but it had a follow-up that tripped me up a bit. Permutations are classic but the circular twist is where things got interesting.

Questions Asked (1)

Q1

Given N students standing in a line, print all possible arrangements. Follow-up: what if the students are arranged in a circle instead?

Algorithms & Data Structures
Author's notes

The base case felt fine, standard backtracking, swap and recurse.

Create a free account to read the full note

AI HintsAI Generated

Suggested Approach

Start by clarifying the problem: permutations of N distinct students in a line, and then in a circle. Explain a backtracking/recursive approach to generate all permutations, and for the circular case, note that rotations are equivalent, so fix one student and permute the rest.

Pro tip: Mention that for the circular case, fixing one element reduces the problem to (N-1)! permutations, and discuss handling duplicates if students are not distinct. Also, consider edge cases like N=0 or N=1.

1. Clarify the problem

Confirm that students are distinct, and that 'arrangements' means permutations. Ask if the order matters and if there are any constraints (e.g., duplicates).

2. Explain the line case

Describe a recursive backtracking algorithm: swap each element with the current position and recurse. Mention time complexity O(N!) and space O(N) for recursion stack.

3. Address the circular case

Explain that in a circle, rotations are considered the same arrangement. Fix one student (e.g., the first) to break rotational symmetry, then permute the remaining N-1 students.

4. Discuss implementation details

Mention how to avoid duplicates if there are identical students (e.g., use a set or sort and skip duplicates). Also, discuss iterative vs recursive approaches.

5. Analyze complexity and edge cases

State time complexity: O(N!) for line, O((N-1)!) for circle. Handle edge cases: N=0 (empty), N=1 (single arrangement).

Key Points to Mention

  • Permutations vs combinations: order matters for arrangements.
  • Backtracking algorithm: swap-based or used-array approach.
  • Circular permutations: fix one element to avoid rotational duplicates.
  • Time complexity: O(N!) for line, O((N-1)!) for circle.
  • Handling duplicates: use a set or skip identical elements.
  • Edge cases: N=0, N=1, and large N (factorial growth).

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.