I went straight to a trie and started coding before I'd thought through what to store at each node.
Start by clarifying the problem constraints (e.g., number of queries, prefixes, and expected query frequency) and then propose a trie-based solution where each node stores a sorted list of queries for the prefix ending at that node. Explain how to preprocess the data by inserting each query into the trie and maintaining the sorted order based on frequency and timestamp, then discuss the time and space trade-offs of this approach.
Pro tip: Mention that you can optimize memory by storing only the top K queries per prefix if the system only needs to return a limited number of results, and discuss how to handle updates if new queries arrive dynamically.
Ask about the scale of data (number of queries, prefixes), whether the data is static or dynamic, and if there's a limit on the number of results per prefix. This ensures your solution aligns with the expected use case.
Describe building a trie where each node represents a prefix and stores a list of queries that have that prefix, sorted by frequency descending and then by earliest timestamp. Explain how to insert queries and maintain the sorted order.
Preprocessing: inserting each query into the trie takes O(L) per query, where L is the query length, plus sorting the lists at each node. Query time: traversing the trie to the prefix node takes O(P) where P is prefix length, then retrieving the sorted list is O(1) if precomputed.
The trie uses O(total characters in all queries) space, but storing sorted lists at each node can increase memory. Optimize by storing only top K results per node or using a heap to merge results on the fly if K is small.
Mention alternative approaches like using a hash map for prefixes or a combination of trie and heap, and discuss how to handle dynamic updates (e.g., new queries) by updating the trie and re-sorting affected nodes.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.