← Meta Interview Insights

Meta·Software Engineer·Technical Phone Screen·Intermediate

IntermediatePrefer not to say
Apr 2026Remote

Summary

Meta SWE technical phone screen, one coding problem with a follow-up. The main question was BST-specific and felt approachable, but the follow-up generalization to an arbitrary binary tree is where things got interesting.

Questions Asked (2)

Q1

Given the root of a Binary Search Tree, find the length of the longest strictly increasing path where consecutive nodes are connected by parent-child edges.

Algorithms & Data Structures
Author's notes

The BST property does most of the work here, you just DFS and only follow edges where the child value is larger than the parent.

Create a free account to read the full note

AI HintsAI Generated

Suggested Approach

Use a post-order DFS that returns the longest strictly increasing path starting at each node. At each node, combine the best increasing paths from left and right children if their values are greater than the node's value, and update a global maximum with the sum of the two longest valid branches plus one.

Pro tip: Clarify that the path must follow parent-child edges and be strictly increasing, so you cannot traverse from a child back to its parent. Also, mention that the global maximum can be updated at each node by considering the sum of the two longest increasing branches, which is a common pattern in tree path problems.

1. Clarify the problem

Confirm that the path must be strictly increasing and follow parent-child edges, and that the path can go through a node's left and right subtrees. Ask if the path can start and end at any nodes.

2. Define recursive function

Define a DFS function that returns the length of the longest strictly increasing path starting at the current node and going downward. This function will be called recursively on children.

3. Process children and combine

For each child, if the child's value is greater than the current node's value, recursively get the longest increasing path from that child. Keep track of the two longest such paths from left and right children.

4. Update global maximum

At each node, the longest increasing path that passes through the node is 1 + the sum of the two longest valid increasing paths from its children. Update a global maximum with this value.

5. Return and analyze complexity

Return 1 + the maximum of the valid increasing paths from children (or 1 if none) to the parent. The time complexity is O(n) and space complexity is O(h) due to recursion stack, where h is the tree height.

Key Points to Mention

  • Strictly increasing condition: only consider child paths where child.val > node.val.
  • Post-order traversal: process children before combining at the parent.
  • Global maximum update: consider paths that go through the node using two branches.
  • Return value: longest increasing path starting at the node going downward.
  • Time and space complexity: O(n) time, O(h) space.
  • Edge cases: empty tree, single node, skewed tree.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Follow-up: how would you generalize your approach if the tree were a general binary tree with no BST ordering guarantees?

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

They said I only needed to explain the approach, no full code.

Create a free account to read the full note

AI HintsAI Generated

Suggested Approach

First, clarify the problem: what operation are we generalizing (e.g., search, validation, insertion)? Then explain that without BST ordering, you must rely on structural traversal and possibly additional data structures or constraints. Discuss trade-offs in time/space complexity and mention alternative approaches like hashing or augmented trees.

Pro tip: Show awareness that the generalization often changes the problem fundamentally—e.g., searching becomes O(n) instead of O(log n)—and that you should ask whether the tree is static or dynamic, as that affects the best solution.

1. Clarify the operation and constraints

Ask which operation (search, insert, delete, validate) and whether the tree is static or dynamic. This determines the feasible approaches.

2. Identify the loss of BST properties

Explain that without ordering, you cannot prune subtrees based on value comparisons, so you must traverse all nodes in the worst case.

3. Propose a general traversal-based solution

For search or validation, use DFS/BFS with O(n) time. For insertion/deletion, you may need to define a policy (e.g., insert at first available spot) or use a balanced tree if order is required.

4. Discuss optimizations and trade-offs

Mention that if frequent searches are needed, you could augment the tree with a hash map or convert to a BST, trading space for time. Also note that some problems (like finding a path) may still be solved efficiently with recursion.

5. Summarize with complexity and alternatives

Conclude with the time/space complexity of your generalized approach and mention when a different data structure (e.g., hash table, heap) would be more appropriate.

Key Points to Mention

  • Loss of O(log n) search; becomes O(n) in general binary tree.
  • Use of DFS/BFS for traversal-based operations.
  • Possibility of augmenting the tree with additional data structures (e.g., hash map) for faster lookup.
  • Trade-offs between time and space when adding ordering or indexing.
  • The importance of clarifying the specific operation and constraints before generalizing.
  • Alternative data structures (e.g., balanced BST, hash table) if ordering is not required but performance is.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.