My first instinct was just to iterate through the whole thing and tally up.
Since the array is sorted, use binary search to find the first non-negative element (or the boundary between negatives and non-negatives). Then compute the count of negatives as the index of that boundary, and the count of positives as the total length minus the index of the first positive element (skipping zeros). Return the maximum of these two counts.
Pro tip: Clarify upfront whether the array can contain zeros and how they should be treated, and mention that binary search gives O(log n) time, which is optimal for a sorted array. Also, handle edge cases like all negatives, all positives, or all zeros.
Confirm with the interviewer that the array is sorted in non-decreasing order, may contain zeros, and that zeros are excluded from both counts. Discuss edge cases such as empty array, all negatives, all positives, or all zeros.
Use binary search to find the index of the first element that is >= 0. This index equals the number of negative numbers.
Use binary search to find the index of the first element that is > 0. The number of positive numbers is the total length minus this index.
Compare the count of negatives and the count of positives, and return the larger value. If the array is empty, return 0.
State that the time complexity is O(log n) due to binary search, and space complexity is O(1). Walk through a few test cases to verify correctness.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.