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Meta·Software Engineer·Technical Phone Screen·Intermediate

Intermediate
Apr 2026

Summary

Meta SWE interview focused entirely on the linked list deep copy problem, which sounds straightforward until they start peeling back layers asking about space optimization and correctness guarantees. More depth than I expected for what looked like a classic problem.

Questions Asked (6)

Q1

Given a singly linked list where each node has a `next` and a `random` pointer (which can point to any node or be null), construct a complete deep copy of the list and return its head.

Algorithms & Data Structures
Author's notes

I jumped straight to the hashmap solution because it's the cleanest to explain under pressure.

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AI HintsAI Generated

Suggested Approach

Use a hash map to map each original node to its copy, then set next and random pointers for the copies. Alternatively, interleave copies with originals to achieve O(1) extra space, then split the lists. Discuss trade-offs between the two approaches.

Pro tip: Clarify whether modifying the original list is allowed; if not, the hash map approach is safer. Also, handle edge cases like empty list and null random pointers explicitly.

1. Clarify requirements and constraints

Ask if the original list can be modified, and confirm that the deep copy should have entirely new nodes with no shared references.

2. Choose an approach

Decide between hash map (O(n) space) and interleaving (O(1) space). Explain the trade-offs and pick one based on constraints.

3. Implement the copy logic

For hash map: first pass creates copies and maps originals to copies; second pass sets next and random pointers. For interleaving: insert copies after originals, set random pointers, then split.

4. Handle edge cases

Check for empty list, single node, and null random pointers. Ensure the copy's random pointer is null when the original's is null.

5. Test and verify

Walk through the code with a small example, verifying that next and random pointers are correctly set and no original nodes are referenced.

Key Points to Mention

  • Hash map approach: mapping original nodes to their copies for O(n) space.
  • Interleaving approach: achieving O(1) extra space by weaving copies into the original list.
  • Time complexity: both approaches are O(n) time.
  • Space complexity: hash map uses O(n) extra space; interleaving uses O(1) extra space (excluding output).
  • Edge cases: empty list, single node, random pointer to null or to itself.
  • Importance of deep copy: new nodes, not references to original nodes.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q2

Walk through the hashmap-based approach: how does it work, and what are its time and space complexities?

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

Pretty comfortable here.

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AI HintsAI Generated

Suggested Approach

Start by clearly defining the problem and the hashmap-based solution, then walk through a concrete example to illustrate how the hashmap stores and retrieves information. Finally, analyze the time and space complexities, explaining why they are O(n) for time and O(n) for space in the worst case.

Pro tip: Mention that while the average time complexity is O(1) per operation, worst-case can degrade to O(n) due to collisions, and briefly discuss how hash functions and collision resolution (e.g., chaining) affect performance. This shows depth and awareness of trade-offs.

1. Restate the problem

Briefly restate the problem to ensure alignment and set the context for the hashmap approach.

2. Explain the hashmap strategy

Describe how the hashmap is used: typically storing elements as keys and their indices or counts as values to enable O(1) lookups.

3. Walk through an example

Use a small example to demonstrate insertion, lookup, and how the hashmap helps solve the problem efficiently.

4. Analyze time complexity

State that each operation (insert, lookup) is O(1) on average, leading to O(n) overall time for n elements, but mention worst-case O(n) per operation.

5. Analyze space complexity

Explain that the hashmap stores up to n elements, so space complexity is O(n).

Key Points to Mention

  • Hashmap provides average O(1) time for insert, delete, and lookup.
  • Overall time complexity is O(n) for processing n elements.
  • Space complexity is O(n) due to storing up to n entries.
  • Collision handling (e.g., chaining) can degrade worst-case time to O(n) per operation.
  • Choice of hash function affects performance.
  • Trade-off: using extra space to achieve faster time.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q3

Can you solve this in O(1) auxiliary space? Describe the interleaving technique where you weave clones into the original list, set random pointers, then separate the two lists.

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

This is where I stumbled a bit.

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AI HintsAI Generated

Suggested Approach

First, confirm the problem: deep copy a linked list where each node has a next and random pointer, using O(1) auxiliary space. Then, describe the three-pass interleaving technique: weave cloned nodes into the original list, set random pointers for clones using the original's random pointers, and finally separate the two lists. Emphasize that this achieves O(n) time and O(1) space by reusing the original list's structure.

Pro tip: Mention that while the interleaving technique is optimal for space, it temporarily mutates the input list, which might be a concern in concurrent or immutable contexts. Also, note that a hash map approach is simpler but uses O(n) space, so the trade-off is space vs. simplicity.

1. Clarify the problem and constraints

Restate the problem: deep copy a linked list with next and random pointers. Confirm that O(1) auxiliary space means no extra data structures like hash maps, and that we can modify the original list temporarily.

2. Weave clones into the original list

Traverse the original list and for each node, create a clone and insert it immediately after the original node. This interleaves the two lists: original1 -> clone1 -> original2 -> clone2 -> ...

3. Set random pointers for clones

Traverse the interleaved list again. For each clone node, set its random pointer to the clone of the original node's random pointer. Since clones are interleaved, original->random->next gives the correct clone.

4. Separate the two lists

Traverse the interleaved list one more time to restore the original list and extract the cloned list. Adjust next pointers to split the interleaved nodes into two separate lists.

5. Analyze complexity and edge cases

State that time complexity is O(n) with three passes, and auxiliary space is O(1) since we only use pointers. Discuss edge cases: empty list, single node, random pointers to null or to itself.

Key Points to Mention

  • The three-pass approach: weave, set randoms, separate.
  • How to set random pointers: clone->random = original->random->next (if original->random is not null).
  • Restoring the original list during separation to avoid side effects.
  • Time complexity O(n) and space complexity O(1).
  • Comparison with hash map approach: O(n) space but simpler; interleaving is more space-efficient but mutates input temporarily.
  • Edge cases: empty list, single node, random pointers to null or to nodes not yet processed.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q4

What happens when random pointers form cycles or point backward in the list? Does your algorithm still work correctly?

Algorithms & Data Structures
Author's notes

Caught me a little flat-footed because I hadn't thought about it explicitly.

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AI HintsAI Generated

Suggested Approach

First, clarify that the algorithm's correctness depends on the specific problem (e.g., deep copy vs. cycle detection) and the algorithm used. Then, explain how the algorithm handles cycles and backward pointers, emphasizing that it should not rely on the list being acyclic or pointers moving forward. Finally, discuss any necessary modifications or assumptions, such as using a hash map to track visited nodes to avoid infinite loops.

Pro tip: Demonstrate awareness that cycles in random pointers can cause infinite loops in naive traversal, so explicitly mention using a visited set or Floyd's cycle detection. Also, relate to real-world scenarios like graph traversal to show depth of understanding.

1. Clarify the problem and algorithm

State the specific problem (e.g., copying a linked list with random pointers) and the algorithm you would use (e.g., hash map based two-pass).

2. Analyze impact of cycles/backward pointers

Explain that cycles or backward pointers can create loops, so the algorithm must handle them without infinite recursion or iteration.

3. Describe handling mechanism

Detail how your algorithm avoids issues, such as using a hash map to map original nodes to copies, ensuring each node is processed once.

4. Confirm correctness

Argue that the algorithm remains correct because it doesn't assume acyclic structure; it treats the list as a graph and copies edges accordingly.

5. Discuss edge cases and alternatives

Mention edge cases like self-loops or multiple cycles, and briefly note alternative approaches (e.g., interleaving nodes) and their trade-offs.

Key Points to Mention

  • Use of a hash map to track visited nodes prevents infinite loops.
  • The algorithm should treat the linked list as a graph, where random pointers are edges.
  • Cycles and backward pointers do not affect correctness if each node is copied exactly once.
  • Time and space complexity remain O(n) with the hash map approach.
  • Alternative in-place algorithms (e.g., interleaving) also handle cycles but require careful pointer manipulation.
  • Testing with cycles is crucial; mention specific test cases like a node pointing to itself or a cycle of two nodes.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q5

How would you verify that the deep copy is structurally correct, including that no copied node's pointer accidentally references a node from the original list?

Algorithms & Data StructuresTechnical Trade-offs
Author's notes

Described checking same length, same values in order, and that each copy's random maps to the same relative index as the original's random.

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AI HintsAI Generated

Suggested Approach

Start by explaining that verification requires both structural and referential integrity checks. Propose a two-pronged strategy: first, traverse both lists in parallel to confirm node values and next/random pointers align; second, use a hash set of original nodes to ensure no copied node's pointers reference the original list. Emphasize that this catches subtle aliasing bugs that simple value comparison misses.

Pro tip: Mention that you would also test edge cases like empty lists, single-node lists, and lists with self-referencing random pointers, and that you'd use a debugger or write a helper function to assert pointer identity, not just equality.

1. Parallel traversal for structural equivalence

Traverse the original and copied lists simultaneously, comparing each node's value and the relative positions of next and random pointers. Ensure the copied list has the same length and that random pointers point to nodes at the same indices.

2. Build a set of original nodes

Collect all nodes from the original list into a hash set (by object identity). This allows O(1) checks to see if any pointer in the copied list references an original node.

3. Verify no cross-references

Traverse the copied list and for each node, check that its next and random pointers are not in the set of original nodes. Also ensure that all pointers are either null or point to nodes within the copied list.

4. Check deep independence

Mutate a value in the copied list and confirm the original list remains unchanged, and vice versa. This confirms that no memory is shared between the two lists.

5. Test edge cases and use assertions

Run tests with empty lists, single nodes, and random pointers that point to themselves or to the head. Use assertions or a debugger to verify pointer identities, not just values.

Key Points to Mention

  • Use of hash set for O(1) identity checks to detect aliasing.
  • Parallel traversal to compare structure and random pointer offsets.
  • Importance of testing edge cases: empty list, single node, self-loop random pointers.
  • Mutation testing to ensure deep independence (no shared memory).
  • Pointer identity vs. value equality: must check object references, not just values.
  • Time and space complexity of verification: O(n) time, O(n) space for the set.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.

Q6

What edge cases does your solution need to handle? Think about an empty list, a single node whose random points to itself, and a list where all random pointers are null.

Algorithms & Data Structures
Author's notes

I listed these pretty quickly.

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AI HintsAI Generated

Suggested Approach

Walk through each edge case systematically, explaining how your solution handles it without breaking. Emphasize the importance of null checks, self-references, and maintaining the original list's structure. Conclude by discussing how these edge cases are covered in your testing strategy.

Pro tip: Mention that you would write unit tests for each edge case before coding, and that handling these cases early prevents subtle bugs like infinite loops or null pointer exceptions.

1. Identify the edge cases

List the specific edge cases mentioned: empty list, single node with random pointing to itself, and all random pointers null. Also consider other potential edge cases like two nodes pointing to each other.

2. Explain handling for each case

For each edge case, describe how your algorithm avoids errors. For example, for an empty list, return null immediately; for a self-referencing node, ensure the copy's random points to itself, not the original.

3. Discuss algorithmic implications

Explain how these edge cases affect your approach, such as the need for a hash map to track original-to-copy mappings to handle random pointers correctly.

4. Highlight testing strategy

Mention that you would write unit tests for each edge case to verify correctness, including checking that the original list is not modified.

Key Points to Mention

  • Empty list: return null or empty list without errors.
  • Single node with random pointing to itself: ensure the copy's random points to the copy, not the original.
  • All random pointers null: the copy should also have all random pointers null.
  • Use a hash map to map original nodes to their copies to handle random pointers.
  • Preserve the original list's structure; do not modify it.
  • Test edge cases explicitly to avoid infinite loops or null pointer exceptions.

AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.