The heap angle is pretty obvious once you think about it for a minute, keep a min-heap of size k and the top is always your answer.
Start by clarifying requirements: k is fixed, and we need to support add and query k-th largest efficiently. Then propose a min-heap of size k to maintain the k largest elements, where the root is the k-th largest. Discuss time and space complexity, and handle edge cases like k > number of elements.
Pro tip: Mention that if k is large or the stream is unbounded, a balanced BST or order-statistic tree could be used, but a heap is optimal for typical k. Also, note that if k can change, the design would differ.
Ask if k is fixed, if the initial list can be empty, and what should be returned if fewer than k elements have been seen. Confirm that add returns the k-th largest after insertion.
Propose a min-heap of size k to store the k largest elements seen so far. The root of the heap is the k-th largest element.
For each new value, if heap size < k, push it; else if value > heap root, pop root and push value. Then return heap root if size == k, else indicate not enough elements.
Explain that each add takes O(log k) time and O(k) space. Initialization from list takes O(n log k) if done naively, but can be optimized to O(n) using heapify if we only need k largest.
Handle k=1 (max element), k larger than stream size, and duplicate values. Mention alternatives like quickselect for static data or balanced BST for dynamic k.
AI-generated suggestions, not part of the candidate's original notes. May be inaccurate — verify before relying on them.